I’m not really sure but I think if u search it up u would get it
Answer:
m = 11/9
Step-by-step explanation:
m = (y2 - y1) / (x2 - x1)
= (-7 - 4) / (-3 - 6)
= -11/-9
= 11/9
Answer: First option is correct.
Step-by-step explanation:
Since we have given that
![6x^3+6](https://tex.z-dn.net/?f=6x%5E3%2B6)
Now, by factorising , we get
![6x^3+6\\=6(x^3+1)](https://tex.z-dn.net/?f=6x%5E3%2B6%5C%5C%3D6%28x%5E3%2B1%29)
Now, we use the formula i.e.
![a^3+b^3=(a+b)(a^2-ab+b^2)](https://tex.z-dn.net/?f=a%5E3%2Bb%5E3%3D%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29)
By using this, we get ,
![6(x^3+1)\\=6(x+1)(x^2-x+1)](https://tex.z-dn.net/?f=6%28x%5E3%2B1%29%5C%5C%3D6%28x%2B1%29%28x%5E2-x%2B1%29)
So,
![(x+1) \text{ is the factor of }6x^3+6.](https://tex.z-dn.net/?f=%28x%2B1%29%20%5Ctext%7B%20is%20the%20factor%20of%20%7D6x%5E3%2B6.)
Answer:
$30
Step-by-step explanation:
Calculation for the tickets that must be purchased for Carnival T and Carnival Q to be the same
Based on the information given let x be the number of ticket to be purchased .
Carnival T entrance fee= $7.00
Ride= $0.50 per ticket
Carnival Q entree fee =12.00
Ride= $0.25 per ticket
Tickets=$7.00 + ($0.50* x) = $12.00 + ($0.25* x)
.25 x = 5.00
Hence:
x=$.25+$5.00
×=$30
Therefore the amount of tickets that must be purchased in order for the total cost at Carnival T and Carnival Q to be the same will be $30
Answer:
27 chocolate cake and 12 pecan cake
Step-by-step explanation: