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3 years ago

Find the value of x.

Mathematics

2 answers:

Deffense [45]3 years ago

4 0

The.value of x woukd be 2

jeyben [28]3 years ago

3 0

Check the picture below.

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~work out the size of one exterior angle of a regular hexagon ~

Rudik [331]

Answer: What do you mean "Regular Hexagon"

Step-by-step explanation:

7 0

3 years ago

Solve on the interval (0,2pi)<br><br> 3 cscx-1=2

Musya8 [376]

Answer:

It is pi/2

Step-by-step explanation:

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3 years ago

Adrian just got hired for a new job and will make $66,000 in his first year. Adrian was told that he can expect to get raises of

Ann [662]

Answer:

Adrian would make $196000 in his 26th year working.

Step-by-step explanation:

Adrian salary in first year = $66,000

As Adrian is expected to get raises of $5,000 every year going forward.

Here is the sequence of Adrian's raises:

5,000, 10000, 15000, 20000, 25000 .....

As the common difference between consecutive terms is constant.

d = 10000 - 5,000 = 5,000 ⇒ d = 15000 - 10000 = 5,000

So, Adrian's raises is in Arithmetic sequence.

a₁ = 5,000

n = 26

$\ a_{n}=a_{1}+(n-1)d$

Put n = 26 to get the total amount of salary raises in Adrian's 26th year.

$\ a_{26}=5000+(26-1)5000$

$\ a_{26}=5000+(25)5000$

$\ a_{26}=5000+125000$

$\ a_{26}=130000$

Total raises amount after 26th year = $130000

Adding total raises after 26th year to the initial salary would let us figure out the total salary Adrian would make in his 26th year.

So,

Total Salary after 26th year = initial salary + total raises of 26 years

= 66000 + 130000

= $196000

So, Adrian would make $196000 in his 26th year working.

<em>Keywords: arithmetic sequence, salary, raises, common difference</em>

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6 0

3 years ago

12 - 33/4 equal in fraction form?

Anastasy [175]

The answer is 3 3/4
Happy Holidays!

8 0

2 years ago

Read 2 more answers

Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even. what kind of proof did you

scoray [572]

Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n

Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.

6 0

4 years ago