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2 years ago

Solve on the interval (0,2pi) 3 cscx-1=2

Mathematics

1 answer:

Musya8 [376]2 years ago

5 0

Answer:

It is pi/2

Step-by-step explanation:

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Please help, Will mark brainliest

mihalych1998 [28]

Answer:

y = - 8 x + 2

Step-by-step explanation:

Use any two pairs to find the slope with

slope = (y2-y1)/(x2-x1)

for example: (0, 2), and (1, -6)

slope = (- 6 - 2) / (1 - 0) = - 8

so the equation should look like:

y = -8 x + b

use point (0, 2) to find b:

2 = - 8 (0) + b

b = 2

Then

y = - 8 x + 2

5 0

3 years ago

Use the simple interest formula to find the ending balance.

9966 [12]

Answer: 13,000

Step-by-step explanation:

I = prt

I = (.65)($4000)(5)

I = 2600(5)

I = 13,000

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3 years ago

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kupik [55]

I believe it would be 12/18 so that would be 2/3 and 0.6 in decimal form

4 0

2 years ago

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The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct

lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

$y=\dfrac{x}{1+x}$

Point $P\left(1,\dfrac{1}{2}\right)$ lies on the curve.

Point $Q\left(x,\dfrac{x}{1+x}\right)$ is an arbitrary point on the curve.

The slope of the secant line PQ is

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]$