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Brrunno [24]
3 years ago
14

What graph is the graph of y ≥ 1 - 3x?

Mathematics
2 answers:
amid [387]3 years ago
5 0

Answer:

The graph of given equality is shown below.

Step-by-step explanation:

The slope intercept form of a line is

y=mx+b          .... (1)

where, m is slope and b is y-intercept.

The given inequality is

y\geq 1-3x

The related equation of the given inequality is

y=1-3x              .... (2)

On comparing (1) and (2), we get

m=-3, b=1

It means the slope of the line is -3 and y-intercept is 1. The graph of related line is a solid line because the sign of inequality is ≥.

Check the given inequality by (0,0).

0\geq 1-3(0)

0\geq 1

This statement is false. So, (0,0) is not included in the solution set.

Therefore, the graph of given equality is shown below.

siniylev [52]3 years ago
4 0
<h2>Greetings!</h2>

First of all option C and D are ruled out because no area is shaded. Because the values of Y are all ≥ 1 - 3x the area shaded should be above the line and the line should not be dotted, it should be a full line. Although there seems to be no option for both a full line and above the line is shaded.


<h2>Hope this helps!</h2>
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Answer:

The radian :

\frac{2\pi}{3}

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2 years ago
Shown are the number of baskets made by Mark in 10 basketball games-
m_a_m_a [10]
Mean means u add then divide so it’s 80/10=8
5 0
2 years ago
An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

8 0
3 years ago
!!!!(Help me please)!!!!
Leona [35]

Answer:

The correct option is C

Step-by-step explanation:

A: We know that the lower quartile is 144, and the upper quartile is 129.5 is you add them all up it is going to equal 273.3. So we know that A can now be crossed out.

B: We know that the lower quartile is 146, and that means the upper quartile is 136.5. So adding all of these numbers up we ill get 282.5 So now <u>B can be crossed out</u>

C: The lower quartile is 114 and the upper quartile is 129.5 and when we add those two numbers up we are going to get 243.5. So we are going to keep this number

D: For the last one we know the lower quartile is 214 and upper is 129.5, and when we add this we get 343.5. So we can cross this out and<u> the only one we have left is going to be C</u>

<u>Hope this help's</u>

3 0
2 years ago
Read 2 more answers
Find the area of a plane figure bounded by lines
natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6   ⇒   x² + x - 2 = 0   ⇒   (x + 2)(x - 1) = 0   ⇒   x = -2, x = 1

Now, integrate from x = -2 to x = 1

\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,    <em>the bottom of the integral is -2 </em>

= \int\limits^1_2 {x+6-x^{2}-2x-4 } \,

= \int\limits^1_2 {-x^{2}-x+2 } \,  

= \frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,

= (\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))

= (\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)

= \frac{-9}{3} + \frac{3}{2} +6

= -3 + 1.5 + 6

= 4.5


3 0
3 years ago
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