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antiseptic1488 [7]
3 years ago
12

The middle note C has a frequency of 262 hertz and can be modeled using a sine function with an amplitude of 1.5, where x is tim

e in seconds. Which function represents the vibrations of this note?
Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

Answer:

y=3/2 sin (524πx) or B

Step-by-step explanation:

The question tells you that that the frequency is 262 so you plug 262 in for F so you get 262 =  IBI/2π and once you solve for B you get 524π and you plug that in for B. also the amplitude is 1.5 and 1.5 is the same thing as 3/2.

MrRissso [65]3 years ago
3 0

Answer:  f(x) = 1.5*sin(x*2*pi/0.0038s)

Step-by-step explanation:

A sine function is:

f(x) = A*sin(c*x + f)

Where A is the amplitude, we know that it is 1.5

c is a constant that depends on the frequency.

f is a phase.

As there is no mention of a phase, we can assume f = 0.

Then our function is:

f(x) = 1.5*sin(c*x)

now let's find the value of c.

We know that the frequency is 262hz.

Then the period can be calculated with the equation:

T = 1/f.

T = 1/262 Hz = 0.0038 seconds.

Now, the period of a sin function is 2*pi.

whit pi = 3.14159265358979.....

Then we have that:

sin(0) = sin(c*0.0038s)

sin(0) = sin(2*pi)

then:

c*0.0038s = 2*pi

c = 2*pi/0.0038s

Then the function is:

f(x) = 1.5*sin(x* 2*pi/0.0038s)

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notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

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The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

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0.0001\sqrt{n} = 2.327*0.0003

\sqrt{n} = \frac{2.327*0.0003}{0.0001}

(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2

n = 48.73

Rounding up

49 measurements are needed.

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