3 years ago

Here's another Math one worth 10.

1 answer:

7 0

In a 30-60-90 triangle the side opposite the 30 degree angle is half the length of the hypotenuse.
The short leg is the side opposite the 30 degree angle. If the short leg =x, then the hypotenuse = 2x

The ratio of the short leg to the hypotenuse in the given triangle is cos(60°)

$
cos(60^o) = \frac{adjacent \ side}{hypotenuse } = \frac{x}{2x} = \frac{1}{2}$

Answer is C. 1:2

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