The questions for this problem would be:
1. What is the dimensions of the box that has the maximum volume?
2. What is the maximum volume of the box?
Volume of a rectangular box = length x width x height
From the problem statement,
length = 12 - 2x
width = 9 - 2x
height = x
where x is the height of the box or the side of the equal squares from each corner and turning up the sides
V = (12-2x) (9-2x) (x)
V = (12 - 2x) (9x - 2x^2)
V = 108x - 24x^2 -18x^2 + 4x^3
V = 4x^3 - 42x^2 + 108x
To maximize the volume, we differentiate the expression of the volume and equate it to zero.
V = 4x^3 - 42x^2 + 108x
dV/dx = 12x^2 - 84x + 108
12x^2 - 84x + 108 = 0x^2 - 7x + 9 = 0
Solving for x,
x1 = 5.30 ; Volume = -11.872 (cannot be negative)
x2 = 1.70 ; Volume = 81.872
So, the answers are as follows:
1. What is the dimensions of the box that has the maximum volume?
length = 12 - 2x = 8.60
width = 9 - 2x = 5.60
height = x = 1.70
2. What is the maximum volume of the box?
Volume = 81.872
Answer:
Its 5
Step-by-step explanation:
Mean= sum/number
=80/16
=5
Answer:
a. the cost of the t-shirt
b. x+12=34
c. x=22
d. t-shirt cost 22$
Answer:
The associative property of integers does not hold true for subtraction and division of integers, as, in the case of subtraction and division, the order of the numbers is important and cannot be changed.
Step-by-step explanation:
For example, 2 - (8 - 9) = 2 - (-1) = 3. Now, if we change the order as 8 - (2 - 9) = 8 - (-7) = 15
