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2 years ago

I keep getting (10,5) or (0,5) someone pls help

Mathematics

1 answer:

rodikova [14]2 years ago

4 0

Answer:

(4,-3)

Step-by-step explanation:

Multiplying the bottom equation by -6, we get -6x+12y=-60.

Adding this to the first equation gives 15y=-45, and thus y=-3.

So, it follows that 6x+3(-3)=15, and thus x=4.

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A pipe is leaking at 1.5 cups per day about how many gallons per week is the pipe leaking

yawa3891 [41]

1 U.S. CUP - 0.0625 U.S. GALLONS

So? Convert the cups to gallons.

7 DAYS/PER WEEK

1.5 x 7 = 10.5

So... half a cup is about 0.03125 gallons.

0.03125 + (10 x 0.0625) = ???

Drum roll please...

Plot twist: You can do it yourself.

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3 years ago

Write a linear inequality to represent the information given. Shanley would like to give $5 gift cards and $7 teddy bears as par

ozzi

Answer:

154 is less than or equal to 5x+7y

Step-by-step explanation:

x = number of gift cards and y= number of teddy bears

8 0

2 years ago

Sally has a discount card that reduces the price of her grocery bill in a certain grocery store

ki77a [65]

0.95c

100% minus 5% is 95%, or 0.95. This means Sally only has to pay 0.95 times the grocery bill, or c, which represents 0.95c.

7 0

3 years ago

What does the underlined conjunction connect in the sentence? The family enjoyed fishing, but they loved hiking during their tri

pychu [463]

The answer is c objects

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3 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

Step:-1

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

Answer:-

using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.

4 0

3 years ago