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goldenfox [79]
3 years ago
13

he production of pipes has a mean diameter of 3.25 inches and a standard deviation of .15 inches. The shape of the distribution

is approximated by a normal distribution since approximately an equal number of parts are above or below average, and most parts are very close to the mean value. A part will be discarded is it has a diameter of greater than 3.5 inches or less than 3 inches. What proportion of parts are discarded from the production line
Mathematics
1 answer:
o-na [289]3 years ago
7 0

Answer:

The probability that a randomly chosen part has diameter of 3.5 inches or more is 0.9525

Step-by-step explanation:

Mean = \mu = 3.25 inches

Standard deviation = \sigma = 0.15 inches

We are supposed to determine the probability that a randomly chosen part has diameter of 3.5 inches or more

P(Z \geq 3.5)=1-P(z

Refer the z table for p value

P(Z \geq 3.5)=1-0.0475\\P(Z \geq 3.5)=0.9525

Hence  the probability that a randomly chosen part has diameter of 3.5 inches or more is 0.9525

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Perform the following computations.You may use13≈0.333333,34= 0.75 and100301= 0.332226.(i). Compute13+34by using five significan
White raven [17]

Answer:

a. 1.0833

Absolute Error = 0.416667

Relative Error = 1.250002

b. 0.0011070

Absolute Error = 0.0011070

Relative Error = 0.003321

Step-by-step explanation:

Given

1/3 = 0.333333

3/4 = 0.75

100/301 = 0.332226

a.

1/3 + 3/4

= 0.333333 + 0.75

= 1.083333

= 1.0833 ------ Approximated to 5 significant digits

Absolute Error = |Real Value - Estimated Value|

Relative Error = Absolute Error/Real Value

Assume 1/3 to be the real value and 3/4 to be the estimated value

Absolute Error = |0.333333 - 0.75|

Absolute Error = |-0.416667|

Absolute Error = 0.416667

Relative Error = 0.416667/0.333333

Relative Error = 1.250002

b.

1/3 - 100/301

= 0.333333 - 0.332226

= 0.001107

= 0.0011070 ----- Approximated to 5 significant digits

Assume 1/3 to be real value and 100/301 to be estimated value

Absolute Error = 0.333333 - 0.332226

Absolute Error = 0.0011070

Relative Error = 0.0011070/0.333333

Relative Error = 0.003321

Absolute and relative errors are approximation errors and they are due to the discrepancy between an exact value and some approximation to them.

The absolute error is the magnitude of the difference between the exact value and the approximation. The relative error is the absolute error divided by the magnitude of the exact value

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3 years ago
Of 80 t-shirts, 10% are white, 30% are blue and the rest are red. How many are red?
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