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Illusion [34]
4 years ago
10

What is an attribute of a fractional equation?

Mathematics
2 answers:
irakobra [83]4 years ago
7 0
 Fractional equations are those equations in which the unknown or variable is in the denominator of the fraction.
 To solve this type of equation, you must apply operations with algebraic fractions and pass the variable to the numerator and clearing it to find its value.
 As you can see in the following equation, the variable "x" is in the denominator, so you can identify it as a fractional equation:
 (1/3x+1)=2x/(x-1)
Ghella [55]4 years ago
6 0
There is a variable in the denominator of at least one involved fraction.<span>
</span>
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What is the value of n in the equation 3n + 2(n + 2) = 9n + 12?<br><br> −4<br> −2<br> 2<br> 4
iren [92.7K]
<span>n = -2 is the correct answer</span>
6 0
4 years ago
Solve using identities [0,2) cos2x=sinx
bekas [8.4K]
We have:

\cos 2x = 1 - 2 \sin^2 x

Thus:

1 - 2 \sin^2 x = \sin x

Adding 2 \sin^2 x - 1 gives:

2 \sin^2 x + \sin x - 1 = 0

Factoring gives:

(2 \sin x + 1)(\sin x - 1) = 0

Thus, we have:

\sin x = \frac{-1}{2}

or

\sin x = 1.

Note that because 2 \pi > 2, there will be no solutions y of the form 2n\pi + z for positive integer n and solution z.  So we find the basic values of x giving \sin x \in (\frac{-1}{2}, 1).

For \sin x = \frac{-1}{2} with positive x, x > \pi > 2 (this can be seen easily from the unit circle.  But x < 2, a contradiction.  So we examine the case in which \sin x = 1.

In this case, x = \frac{\pi}{2}.  So this is the only solution to this equation.

Substituting this back in, we have \sin \frac{\pi}{2} = \cos \pi = 1, as desired.  So this is a valid solution.

Thus, x = \frac{\pi}{2}.
7 0
3 years ago
What is 9.03×10^2 in standard form
yawa3891 [41]
9.03 * 10² =
9.03 * 100 =
903
4 0
3 years ago
Please Help!
KonstantinChe [14]

Answer:

y = x^2 - 6 and y = x - 4

Step-by-step explanation:

It's x^2 - 6, because the parabola was moved 6 down, and positive slope, so in the linear, x is positive

7 0
2 years ago
Find the exact value of: sin13pi/8
Vikentia [17]
Sin(13π/8) , is in quadrant IV so the angle will be negative, find the reference angle. 

<span>sin(13π/8) = -sin(16π/8 - 13π/8) = -sin(3π/8) = -cos(4π/8 - 3π/8) = - cos(π/8). </span>

<span>Use half angle formula for cos(x): </span>
<span>cos²(x/2) = (cos(x) + 1) / 2 </span>
<span>Let x = π/4 </span>
<span>cos²(π/8) = (cos(π/4) + 1) / 2 </span>
<span>cos²(π/8) = (√(2) / 2 + 1) / 2 </span>
<span>cos(π/8) = √(√(2) / 4 + 1/2) </span>

<span>-cos(π/8) = -√((√(2) + 2) / 4)</span>
7 0
4 years ago
Read 2 more answers
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