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disa [49]
3 years ago
5

Navigators locate an object by measuring its location clockwise direction from due north. The measure of the angle is called the

bearing. Suppose a lighthouse's bearing is 135° from an island. Be sure to show and explain all work for each part. Part 1: Find the angle represented by the lighthouse on the unit circle. Part 2: Determine the exact ordered pair associated with the lighthouse on the unit circle. Part 3: Find the exact sine, cosine, and tangent of the angle on the unit circle.
Mathematics
1 answer:
kotegsom [21]3 years ago
5 0

Answer:

  • <em>Refer to attached.</em>

Part 1

  • Since bearing is taken from north, i.e. 90°, this will be represented by -45° on the units circle.

Part 2

  • The ordered pair is: (0.707, -0.707)

Part 3

  • sin (-45°) = -√2/2
  • cos (-45°) = √2/2
  • tan (-45°) = -1

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I need help with this problem 4÷36.2 in long Division
nikitadnepr [17]
4 goes into 36 9 times and 36-36 is zero. Bring down the 2 and at a zero to it so it will be 20. Finally, 4 goes into 20 5 times. Your answer is 9.5
3 0
2 years ago
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If your chances of winning a game are 4 out of 10, that’s better than having chances of 2 out of 10.
Nina [5.8K]

Answer:

It is true.

Step-by-step explanation:

4/10 which is 0.4 is a higher probability than 2/10 which is 0.2.

Hope it helped :)

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3 years ago
Pump a can empty a pool in 20 hours and pump b can empty it in 24 hours. working together, how long
Umnica [9.8K]
I would guess 4 hours in that case
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2 years ago
Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
3 years ago
The mean and standard deviation of a normal distribution are 150 and 12 respectively. What percentage of values lie between:
Semenov [28]

Answer:

Step-by-step explanation:

Use a calculator with built-in statistical functions.  The function applying here is normcdf(, the "cumulative density function."  

(a) The percentage of values lying between 138 and 162 is

norm(138,162, 150, 12), which comes out to 0.683, or 68.3%.

(b)  Find norm(126, 174, 150,12):  0.945, or 94.5%

(c)  Find norm(126,162, 150,12);  0.819, or 81.9%

(d) Find norm(162, 174,150,12):  0.136, or 13.6%

8 0
3 years ago
Read 2 more answers
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