Hello.
Taking a look at our screenshot provided, we can conclude that we need to find the missing angle degree out of 90 degrees, as we are dealing with a right angle.
Let's set this up as an Algebraic formula and solve for the variable;
5x + 15 + 50 = 90
First, let's combine like-terms (15 and 50).
5x + 65 = 90
Now, isolate our variable by subtracting 65 from each side of the equation.
90 - 65 = 25
65 - 65 = 0
5x = 25
Now, divide both sides by 5 to solve for x, our missing angle degree.
x = 5
Your answer is A.) 5
I hope this helps!
Line Segment WX=4
Line Segment XY=4
Line Segment YZ=4
Line Segment ZW=4
4+4+4+4=16
The perimeter is 16 units.
i dont quite get the question but...
i guess this is how it is.
Take the mirror image of∆ABC Through the a line through the point y=3.
The new ∆ABC would have point C=(4,2)
B=(3,-6) A=(1,-3)
Now shifting the ∆ABC one unit (<em>i.e. 2 acc. to the graph as scale is 1 unit =2</em>) towards right ( or <em>adding 2 to the x coordinates of ∆ABC)</em>
We get the Coordinates of triangle ABC as A=(3,-3) B=(5,-6) C=(6,2).
This coordinate is the same coordinates of ∆A"B"C".
Hope it helps...
Regards;
Leukonov/Olegion.
A AsA the angle a and d are equal and side ae and de are egual and angles e are equal
