Answer:
is there a picture that u could send
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
a = z/mb
Step-by-step explanation:
Given:

To solve for a, divide both sides by the variables mb to isolate a-term.

Simplify the expression and we finally have solved for a-term.

Therefore, the answer to this question is a = z/mb.
Please let me know if you have any questions regarding my answer or explanation!
Answer:
2
1
-0
-1
-2
1
Step-by-step explanation:
300x80=24,000
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<h3>ANS IS IN THE PIC</h3>
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