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timama [110]
3 years ago
11

Which list contains ONLY irrational numbers?

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
8 0
The first choice is the contains only irrational number
chubhunter [2.5K]3 years ago
4 0

Answer:

The correct option is A.

Step-by-step explanation:

A real number is called a rational number if it can be represented as p/q, where p and q are two integers and q≠0. For example: 2,4/5, 0.2.

A real number is called an irrational number if it can not be represented as p/q, where p and q are two integers and q≠0. For example: π, √2, 2.333....

In option A, all numbers are irrational numbers.

Therefore option A is correct.

In option B,

\sqrt{9}=3

3 is a rational numbers, so √9 is a rational number.

Therefore option B is incorrect.

In option C,

\sqrt{144}=12

12 is a rational numbers, so √144 is a rational number.

Therefore option C is incorrect.

In option D,

\sqrt{121}=11

11 is a rational numbers, so √121 is a rational number.

Therefore option D is incorrect.

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128

Step-by-step explanation:

2 to the power of 7 means you multiply 2 seven times over

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3 0
2 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
Solve each system using a matrix<br> 7x+2y=5<br> 13x+14y=-1
Svetach [21]

Solve each system using a matrix

7x+2y=5

13x+14y=-1Solve each system using a matrix

7x+2y=5

13x+14y=-1

7 0
2 years ago
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