3x+3y+6z=9
x+3y+2z=5
3x+12y+12z=18
Step 1: use Eq 2 to solve for x
x+3y+2z=5
x= -3y-2z+5
Step 2: Solve for y unsing Eq 1
3x+3y+6z=9
3y= -3x-6z+9
y= -x-2z+3
Step 3: plug in x= -3y-2z+5 to solve for the value of y
y=-x-2z+3
y= (-1)(-3y -2z +5) - 2z+3
y= 3y+2z-5- 2z+3
-2y= -2
y=1
Step 4: plug y= 1 into the x= equation
x= -3y-2z+5
x= -3(1)-2z+5
x= -2z+2
Step 5:Plug y= 1 and x= -2z+2 into the 3rd equation to solve for z
3x+12y+12z=18
12z= -3(-2z+2)-12(1)+ 18
12z= 6z - 6 - 12 +18
6z= -18+18
6z=0
z=0
Step 6: Plug z in to solve for x
x=-2z+2
x= (-2)(0)+2
x= 2
ANSWER:
x,y,z = 2,1,0
answer choice C
Answer:
7
Step-by-step explanation:
Answer:
(x+2)(x-2) = 0
Step-by-step explanation:
50%
You have half of 6 so the percentage would be half of 100
Answer:
B)
Step-by-step explanation:
For the function 
, all coordinates this line passes through should make this inequality true.
This corresponds with table B.
