Question

The number of dogs in a city is declining at a rate of about .08% each

Answer 1

Answer:

There will be 3472 cats in 10 years

Step-by-step explanation:

There were 3500 cats

The number of dogs in a city is declining at a rate of about 0.08% each  year.

We are supposed to find the no. of cats in 10 years

Formula :$N(t)=N_0(1-r)^t$

Where N(t) = Remaining cats after t days

$N_0$ = Initial population

r = rate of depreciation

t=time

So, No. of cats remained after 10 years = $3500(1-\frac{0.08}{100})^{10}=3472.100$

Hence There will be 3472 cats in 10 years