The number of dogs in a city is declining at a rate of about .08% each
1 answer:
Answer:
There will be 3472 cats in 10 years
Step-by-step explanation:
There were 3500 cats
The number of dogs in a city is declining at a rate of about 0.08% each year.
We are supposed to find the no. of cats in 10 years
Formula :
Where N(t) = Remaining cats after t days
= Initial population
r = rate of depreciation
t=time
So, No. of cats remained after 10 years =
Hence There will be 3472 cats in 10 years
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Answer:
11.42 boxes
Step-by-step explanation:
For the first box bought, there is a 100% chance of getting a unique toy (since you still don't have any). E₁ = 1.
After that, there is a 4 in 5 chance of getting a unique toy from the next box, the expected number of boxes required is:
For the next unique toy, there is now a 3 in 5 chance of getting it:
Following that logic, there is a 2 in 5 chance of getting the 4th unique toy:
Finally, there is a 1 in 5 chance to get the last unique toy:
The expected number of boxes to obtain a full set is: