Since B is perpendicular to A. We can say that the gradient of B will be -1/7 (product of the gradients of 2 perpendicular lines has to be -1).
Now we know that the equation for B is y=-(1/7)x + c with c being the y intercept.
Since the point isnt specified in the question, we could leave the equation like this.
But if there is a given point that B passes through, just plug in the x and y values into their respective places and solve to find c. That should give you the equation for b.
Now, to find the solution of x, we have 2 equations:
1) y=7x+12
2)y=-(1/7)x+c
In this simultaneous equation we see that y is equal to both the expressions. So,
7x+12=-(1/7)x+c
Now, since the value of c is not found, we cannot actually find the value of x, but if we would find c, we could also find x since it would only be a matter of rearranging the equation.
And there you go, that is your solution :)
<span><span>Make it a solid line for y≤ or y≥, and a dashed line for y< or y>
</span><span>Shade above the line for a "greater than" (y> or y≥)
or below the line for a "less than" (y< or y≤).
So, the answer is A) </span></span><span>x + 4y ≥ −4
</span><span>x + 4y ≥ −4
4y </span>≥ -x - 4
y ≥ -x/4 - 1
10.49 (5 or more round up)
Answer:
D. {(1,2) , (2,3) , (3,4) , (4,5)}
Step-by-step explanation:
Functions are relations with one output for any unique input. Relations that pass the vertical line test have one output for each input. In this case, D was the only set that met the criteria.
