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Helen [10]
3 years ago
13

An isometric transformation is one in which preserves the shape and size of the pre-image. Which of the following transformation

s will not prove to be isometric?
translation
tessellation
rotation
dilation
Mathematics
2 answers:
AlexFokin [52]3 years ago
5 0
The answer would be dilation
<span>Isometric transformation is one in which preserves the shape and size of the pre-image. </span>Dilation is not isometric because it will enlarge the graph, thus changes the image size. 
Rotation, translation, and tesselation won't change the shape and size.
Triss [41]3 years ago
5 0

Answer

so we are looking for a transformation that preserves size and shape. All the choices given are transformations. Let’s assume you have a picture. You place it on the table in front of you.

Translation: here you slide the picture around the table. All you can do to it is slide it. As such you will not change it’s size or shape. This transformation is isomorphic.

Rotation:

Here you hold down one corner of the picture and move the rest around that point either clockwise or counter clockwise. This does not change the size or shape of the picture so this too is isomorphic.

Tesselation: in a tesselation you try and fill a whole page with the picture. To do this you duplicate the picture over and again and you might need to slide it around and rotate it but again this won’t change the size or shape.

Dilation- here you shrinknor enlarge the picture. So this is the one that will not prove isometric.

Step-by-step explanation:

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There are two zeros: -3 and -1. This is because when you factor f(x)<span>= x^2 + 4x + 3, it becomes f(x) = (x + 3)(x + 1). In order to find the zeros, set f(x) to 0, and then solve for x for both (x + 3) and (x + 1). You can check your answer by substituting either -3 or -1 for x in the equation 0 = </span>x^2 + 4x + 3.
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Is the ordered pair a solution of y ≥ 2x − 5? a. (3, 1) b. (1, −4)
Deffense [45]

Answer:

a. Yes

b. No

Step-by-step explanation:

To find if an ordered pair is a solution to the inequality, substitute its x and y values for the x and y in the inequality and solve. If the equation is true, then it is a solution. If it is not, then it is not a solution.

1) First, substitute the x and y values of (3, 1) into the inequality. So, substitute 3 for x and 1 for y:

1 \geq 2(3)-5\\1\geq 6-5\\1\geq 1

1 is greater than or equal to 1, so (3,1) is a solution.

2) Second, do the same with the point (1, -4). Substitute 1 for x and -4 for y:

-4\geq 2(1)-5\\\\-4\geq 2-5\\-4\geq -3

However, -4 is not greater than or equal to -3, thus (1, -4) is not a solution.

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3 years ago
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Gelneren [198K]

Answer:

  • the roots are unequal (distinct)
  • the roots are irrational
  • the roots are real

Step-by-step explanation:

A description of the roots of a quadratic can be had by looking at the value of the discriminant: b²-4ac, where a, b, c are the coefficients of the standard-form quadratic.

Here, we have a=3, b=6, c=1 so the discriminant is ...

  d = 6² -4(3)(1) = 24

This is a positive integer that is not a perfect square. This value means ...

  • the roots are unequal (distinct)
  • the roots are irrational
  • the roots are real

_____

The interpretation of the discriminant is ...

  • d > 0, distinct real roots
  • d = 0, one real root with multiplicity 2
  • d < 0, complex roots

If d is an integer that is not a perfect square, the roots (or their imaginary part) will be irrational.

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Step-by-step explanation:


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