Question

The number of vehicles a dealership sells varies directly with the money spent on advertising.

Answer 1

Answer:

For each $1000 spent on advertising, the dealership sell 8 vehicles.

Step-by-step explanation:

To find the exact answer, we can find the linear equation and then use it to calculate the number of vehicles sold for each $1000 spent on advertising.

First, we choose two points from the graph $(5,40)(0,0)$, this two points will be used to find the slope.

$m=\frac{40-0}{5-0}=\frac{40}{5}=8$

Now, we use the point-slope formula to find the linear expression:

$y-y_{1}=m(x-x_{1})\\y-0=8(x-0)\\ y=8x$

So, we replace x=1, which represent $1000, and see what value returns for y:

$y=8(1)=8$

Therefore, for each $1000 spent on advertising, the dealership sell 8 vehicles.

Answer 2

Two points I can assuming to have integer coordinates (points without decimals in (x, y) ) are (0, 0) and (5, 40)

From this, I can make a safe assumption that y is 8 times the x value.

since x value is money spent on advertising in $1000s', number of vehicles is 80 times of how much money is spent on advertising in $1000.

But, if you want to be fancy (or I guess this is more correct), 8/1000 = 0.08, so for extra dollar spent, 0.08 more vehicles are sold, rounded down.