⭐ Please consider brainliest! ⭐
✉️ If any further questions, inbox me! ✉️
Answer:
Yes, it would be statistically significant
Step-by-step explanation:
The information given are;
The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%
Number of jawbreakers in the sample, n = 800
The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 = =p
The formula for the standard deviation of a proportion is
Solving for the standard deviation gives;
Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4 in the sample of 800 = 800*0.6 = 480
For statistical significance the difference from the mean = 2× = 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7
The z-score of 494 jawbreakers is given as follows;
Therefore, the z-score more than 2 × which is significant.
Answer = 7x(4x-1) . Hope it helps.
Answer:
y=5sin(16pix)+3
Step-by-step explanation:
Amp=5 means our curve is either y=5sin(bx+c)+d or y=-5sin(bx+c)+d.
y=sin(x) has period 2pi.
So y=sin(bx) has period 2pi/b.
We want 2pi/b=1/8.
Cross multiplying gives: 16pi=b
y=5sin(16pix+c)+d
d=3 since we want midline y=3.
y=5sin(16pix+c)+3
We can choose c=0 since we aren't required to have a certain phase shift.
y=5sin(16pix)+3
unwillingness or disinclination to do something.
or: the property of a magnetic circuit of opposing the passage of magnetic flux lines, equal to the ratio of the magnetomotive force to the magnetic flux