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Maksim231197 [3]
4 years ago
15

Solve to the nearest degree, tan^2 theta--2tan theta=0 in the interval 0 degree a) 63 degree, 180 degree, 243 degree,360 degree

br> b) 0 degree, 63 degree, 180 degree, 243 degree, 360 degree
c) 63 degree, 243 degree
d) 0 degree, 180 degree, 360 degree

Mathematics
1 answer:
qwelly [4]4 years ago
6 0
<span>tg²a-2tga=0
tga(tga-2)=0
tga=0 or tga=2
(</span><span><span>explanation of <span>the picture</span></span>)
Answer:
b) 0 degree, 63 degree, 180 degree, 243 degree, 360 degree</span>

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Answer:

I'm going to lay this out in a chart so it's a little easier to see:

F(x) = f(g(x))

x | f (x) | f ' (x) | g (x) | g ' (x)

--------------------------------------

-2 | 8 | 4 |

5 | | 3 | -2 | 6

Remember the chain rule, which says

(f (g (x))) ' = g ' (x) f ' (g (x))

When they ask for F ' (5), they are asking for (f (g (x))) ' when x = 5.

Using the chain rule, that's

F ' (5) = g ' (5) f ' (g (5))

We can simplify using the numbers provided.

F ' (5) = (6) f ' (-2)

F ' (5) = (6) (4)

F ' (5) = 24

I hope that helps!

by jannat <33

7 0
3 years ago
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