2nd degree and in form
ax^2+bx+c
it is a prabola
the minimum cost is the vertex (every parabola has only one, min or max)
minimum cost is the vertex
vertex=-b/(2a)
a=0.4
b=-208
vertex=-(-208)/(2*0.4)
vertex=208/0.8
vertex=260 (means 260 dresses)
that is x value
subsitute for y value
C(x)=0.4(260)^2-208(260)+37365
C(x)=10325
minimum cost is $10,325
2x3a=6a. 2x2b=4b. 2x-7=-14.
D. 6a+4b-14
The approximate percentage of light remaining after passing through 6 feet of water, to the nearest tenth of a percent is 4.7%
<h3>How is the percentage of light remaining at a depth of 6 feet calculated?</h3>
The percentage of light remaining is calculated from the percentage of light remaining after a depth of one foot each.
Percentage of light remaining after 1 feet = 100 - 40% = 60%.
Percentage of light remaining after 6 feet = 60% × 60% × 60% × 60% × 60% × 60% = 4.7%
Therefore, the approximate percentage of light remaining after passing through 6 feet of water, to the nearest tenth of a percent is 4.7%.
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Answer: %25
Step-by-step explanation: 19/76 = 0.25
