Find the x intercept of the line graphed by the equation 1/2x-7y=7

It costs a family of two $25 to go to the state fair, and a family of six $65. Find the equation, rate of change, and initial va

motikmotik

Answer:

Step-by-step explanation:

Given:

Family of 2

Cost, C1 = $25

Family of 6

Cost, C2 = $65

Given that 2 points are given above as the following in coordinate form:

A(2,25) and B(6,65)

Rate of change is given as = (y2 - y1)/(x2 - x1)

= (65 - 25)/(6-2)

= 40/4

Therefore,

(y - y1)/(x - x1) = (y2 - y1)/(x2 - x1)

(y - 25)/(65 - 25) = (x - 2)/(6 - 2)

(y - 25)/40 = (x - 2)/4

(y - 25) = 40/4 × (x - 2)

(y - 25) = 10 × (x - 2)

Expanding,

y - 25 = 10x - 20

y = 10x - 20 + 25

y = 10x + 5

6 0

3 years ago

A blueprint for a house states that 2 inches represents 8 feet. If the width of a window is 2.5 inches on the blueprint, what is

Sloan [31]

Answer:

10 feet. You can prove this by dividing 8 by 2, with this you find that 1 inch on the blueprint is equal to 4 feet. then take half of 4(2), and add it to 8 to get your answer.

Step-by-step explanation:

I hope this helps you

-KeairaDickson

8 0

4 years ago

A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st

maxonik [38]

Answer:

$z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413$

$p_v =2*P(z>1.413)=0.158$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

Step-by-step explanation:

Data given and notation

$\bar X=5.0611$ represent the sample mean

$\sigma=0.2803$ represent the population standard deviation for the sample

$n=42$ sample size

$\mu_o =5$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is different from 5, the system of hypothesis would be:

Null hypothesis: $\mu = 5$

Alternative hypothesis: $\mu \neq 5$

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(z>1.413)=0.158$

Conclusion

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

8 0

4 years ago

A new video game is expected to sell 102 copies the first hour at a local game store. After that, the sales will follow the func

nikdorinn [45]

S(x) = 102 (102 represents the number of video games sold in the first hour)

s(x)=11(x-1)

102 + 11(x-1)

8 0

4 years ago

Read 2 more answers

Hi there. how are ya buddy

Neko [114]

Answer:

if i remember correctly the answer is 120*