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3 years ago

Which of the following statements is not always true?

Mathematics

2 answers:

coldgirl [10]3 years ago

7 0

Answer:

The correct answer is C

Step-by-step explanation:

trust me

algol [13]3 years ago

4 0

Answer:

Option C

Step-by-step explanation:

Option A: In a rhombus, the diagonals bisect opposite angles.

It is always true.

Option B : In a rhombus, the diagonals are perpendicular.

It is always True.

Option C : . In a rhombus, the diagonals are congruent.

It is not always true. If the diagonals become congruent then It becomes square.

Option D: In a rhombus, all four sides are congruent.

It is always True.

Hence Option C is the statement which is not always true.

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Wyatt makes and sells rope doormats. He uses 200 feet of rope for each doormat. He wants to make 25 doormats. Which expression s

olga_2 [115]

Answer: See explanation

Step-by-step explanation:

First and foremost, we should not that:

1 yard = 3 feet

We are informed that Wyatt uses 200 feet of rope for each doormat and that he wants to make 25 doormats.

The expression that shows a correct way to find how many yards of rope he needs will be:

= (200 × 25) / 3

= 5000/3

= 1666.67 yards

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2 years ago

Find the surface area of the cylinder.Round your answer to the nearest tenth.

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Answer:

The answer is 3438.16 i think

Step-by-step explanation:

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2 years ago

Which of the following is most likely the next step in the series?<br> ⠀⠀

-Dominant- [34]

The next step in the series is choice D.

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1 year ago

Read 2 more answers

There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc

sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and B be the event that student play soccer.

$P(A)=8\%$

$P(B)=14\%$

It is given that 6 students play on both teams.

$P(A\cap B)=\frac{6}{200}\times 100=3\%$

We have to find the probability that a student plays either basketball or soccer.

$P(A\cup B)=P(A)+P(B)-(A\cap B)$

$P(A\cup B)=8\%+14\%-3\%$

$P(A\cup B)=19\%$

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

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3 years ago

sorry! I forgot the picture in my last question. Still trying to figure brainly out lol! I cant figure out the last blank one. S

Liono4ka [1.6K]

Answer:

-1y² the rest is right

Step-by-step explanation:

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2 years ago