Answer:
The correct answer is C
Step-by-step explanation:
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Option C
Option A: In a rhombus, the diagonals bisect opposite angles.
It is always true.
Option B : In a rhombus, the diagonals are perpendicular.
It is always True.
Option C : . In a rhombus, the diagonals are congruent.
It is not always true. If the diagonals become congruent then It becomes square.
Option D: In a rhombus, all four sides are congruent.
Hence Option C is the statement which is not always true.
No, it isn't.
We have and let be the subset of of all points on the line
We need to find if is a subspace of the vector space .
In all the possibilities for own subspace of the vector space are :
We know that is the subset of of all points on the line
If we look at the equation, the point doesn't verify it because :
Which is an absurd. Therefore, doesn't contain the origin (and is a line in ). Finally, it can't be a vector space of
x= -2
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