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shutvik [7]
4 years ago
14

An ancient Greek was born on April 1st, 35 B.C. and died on April 1st, 35 A.D. How many years did he live?

Mathematics
2 answers:
lara [203]4 years ago
6 0

Answer:

70 years

Step-by-step explanation:

35 years before Christ and then another 35 years after:  35 + 35 = 70 years

yawa3891 [41]4 years ago
5 0

Answer:

the answer is 69

Step-by-step explanation:

35bc - 35ad = 69 years, because there is no year 0.

35+35 = 70

70-1=69

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Help please :)<br> You can have 15 points if you answer it correctly (if I'm not mistaken)
dusya [7]

Answer:

$466

Step-by-step explanation:

Represent her salary by s.  Then the amount spent on rent is s/2.

After spending 168 on her electric and water bills, she had s/2 - 168 dollars left.  She spent half of this on her phone bill, leaving her with

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After buying $57 worth of gas, she had

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We must now solve for s.

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Simplifying this, we get s/2 = 168 + 114 + 184, or s/2 = 466.

She spent half her salary (that is, half of s) on rent.  As seen above, this is $466.

7 0
3 years ago
1. Solve -y/12 = 6<br> 2. Solve x/4 = 8
OlgaM077 [116]

1. Isolate the y. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

First, multiply 12 to both sides

-y/12(12) = 6(12)

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Isolate the y. Divide -1 from both sides

-y/-1 = 72/-1

y = -72

-72 is your answer for y

--------------------------------------------------------------------------------------------------------------

2. Isolate the x. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

x/4 = 8

First, multiply 4 to both sides

x/4(4) = 8(4)

x = 8(4)

x = 32

32 is your answer for x

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hope this helps

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C - 29 feet.

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