Sure. From those choices, the only one that makes sense is that he
didn't perform enough trials. Technically, you can't expect the experimental
probability to match the theoretical probability until you've rolled it an infinite
number of times.
I have a hunch that even for only 60 trials, such a great discrepancy between
theory and experiment is beginning to suggest that the cubie is loaded. But
you really can't say. You just have to keep trying and watch how the numbers
add up.
Answer:
The number of child tickets is 53
And adult tickets sold out is 93
Step-by-step explanation:
Let the child tickets be x
And the adult tickets be y
x+y = 146 - - - - - - - 1
x= 146-y
5.3x + 9.3y= 1145.80 - - - - - 2
We can substitute x= 146-y in equation 2
5.3(146-y) + 9.3y= 1145.80 - -- 2
773.8 - 5.3y +9.3y = 1145.80
773.8+4y= 1145.80
4y= 1145.80-773.8
4y= 372
y= 372/4
y= 93
We can now substitute y= 93 in equation 1 to find x
x+ 93= 146
x= 146-93
x= 53
Hence
The number of child tickets is 53
And adult tickets sold out is 93
Its a rectangle so two sides are equal and both sides that are opposite of each other are equal. So two sides are 37. Then you add them together to get 74, then subtract it from 164 to get 90 the rest of the fence length. Then divide it by two to get 45 which is the other side lengths, so it would be a 37 by 45 rectangle one side would be 37 while the other two are 45.
Answer: a discount of 25%
Step-by-step explanation:
if you take any number and take 10 percent off then 15 percent off it’s even but 25 percent off is a better discount because it takes more money off the original price
The proof is given below. Please go through it.
Step-by-step explanation:
To solve Δ ABC ≅ Δ DBC
From Δ ABC and Δ DBC
AB = BD (given)
AC = CD (given)
BC is common side
By SSS condition Δ ABC ≅ Δ DBC ( proved)
To solve Δ EHF ≅ Δ GHF
Δ EHF and Δ GHF
EH = HG ( given)
∠ EFH = ∠ GFH ( each angle is 90°)
HF is common side
By RHS condition
Δ EHF ≅ Δ GHF
