Answer:
1/2 -2/1
Step-by-step explanation:
122
8mar12
212323
123345wqesfef
Theory:
The standard form of set-builder notation is <span>
{ x | “x satisfies a condition” } </span>
This set-builder notation can be read as “the set
of all x such that x (satisfies the condition)”.
For example, { x | x > 0 } is
equivalent to “the set of all x such that x is greater than 0”.
Solution:
In the problem, there are 2 conditions that must
be satisfied:
<span>1st: x must be a real number</span>
In the notation, this is written as “x ε R”.
Where ε means that x is “a member of” and R means “Real number”
<span>2nd: x is greater than or equal to 1</span>
This is written as “x ≥ 1”
Answer:
Combining the 2 conditions into the set-builder
notation:
<span>
X =
{ x | x ε R and x ≥ 1 } </span>
Answer:
x - m/q = t
x = m/q + t is the answer
Area = πr²
Area = 3.14* 6²
A = 3.14 * 36
A = 113.04
Now find the area of the other one.
<span>Area = πr²
A = 3.14 * 0.75</span>²
A = 1.76625
Now subtract them.
113.04 - 1.76625 = 111.27375
Now, we have our answer: A = <span>111.27375
However, I don't see why they told you to have an exact answer for the area. You can't have an exact answer when you use 3.14 for pi.</span>
