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3 years ago

Help me fill in the blanks pleasee

Mathematics

2 answers:

777dan777 [17]3 years ago

8 0

Answers and Step-by-step explanations:

Let's look at the first row:

cost = _______ + _______ * (monthly payment)

The first blank should be the "down payment" because this is the initial, constant value that is paid. The second blank should be the "number of months" because this way, when multiplied by the actual amount each payment is (monthly payment), then we get the total amount paid during those months.

So, we have:

cost = (down payment) + (number of months) * (monthly payment)

Now for the second row, we just plug in numbers and variables:

335 = 50 + 6 * p

Finally, we can solve for p:

335 = 50 + 6p

6p = 285

p = $47.50

docker41 [41]3 years ago

3 0

Answer:

Cost = down payment + no. of monthly payments × monthly payment

335 = 50 + 6 × p

285 = 6p

p = 47.5

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valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

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