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frozen [14]
4 years ago
11

Planes A and B intersect in line s. If point Vis a point on line s, then it lies on:

Mathematics
1 answer:
Trava [24]4 years ago
7 0

Answer:

Option C.

Step-by-step explanation:

It is given that planes A and B intersect in line s.

It means, all points lie on the line s must be lie on both plane A and B because s is the line of intersection of both plane A and B.

It is given that V is a point on line s.

Since, the point V lies on line s, therefore it is also lies on both plane A and B.

Hence, the correct option is C.

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Darina [25.2K]

72+72+36= 144+36= 180

7 0
3 years ago
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What is 135 km/h to ft/s.
Dominik [7]

Answer:

123.035ft/s

Step-by-step explanation:

for an approximate result divide the speed value by 1.097

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What is 6.16×10^6 in standard form?
OleMash [197]
Your answer is  6,160,000 my friend
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A car travels 14km in 25mins . Find out how far the car can travel in 5 hours if the speed remains the same ? ​
jekas [21]
<h3><u>Answer :- </u></h3>

168 km ...

<h3><u>Explanation :- </u></h3>

It is given that the car travels 14km in 25 minutes..

Now , assume that the distance the car travel in 5 hours be x..

  • Since 1 hour = 60 minutes..
  • 5 hours = 300 minutes ..

• Thus , The two given statements are :-

  • 14km -----------------> 25 minutes..
  • And, x km -------------> 300 minutes..

<h3><u>We know that , </u></h3>

  • The distance travelled by car and the time taken by the car is directly proportional to each other....

<h3>So , </h3>

\frac{14}{25}  =  \frac{x}{300}

= x = 168km

• Hence , Car can travel 168km in 5 hours ..

Hope this helps you :)

6 0
2 years ago
A baseball player comes up to bat 3 times during a league game. He either gets a hit or gets an out. How many different combinat
Stella [2.4K]

Answer:

8 different combinations are possible.

Step-by-step explanation:

Here, we have 2 different combinations for each time.

And the player comes out to bat 3 times.

So, total number of combinations are:

2^{3} i.e. a total of 8 number of times.

Let a hit is termed as 'H' and an out is termed as 'O'.

Total combinations are:

{HHH, HHO, HOH, HOO, OHH, OHO, OOH, OOO}

Kindly have a look at the tree diagram attached in the answer area.

In starting, there are 2 combinations possible, i.e. 'O' and 'H'.

After 'O' , 2 possible i.e. 'O' and 'H'.

After 'H' , 2 possible i.e. 'O' and 'H'.

and so on....

8 0
3 years ago
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