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garri49 [273]
3 years ago
15

What are geometric proofs used for?

Mathematics
1 answer:
drek231 [11]3 years ago
4 0

Answer:

Prove if certain shapes fit the criteria, and if they are congruent or not

Step-by-step explanation:

Geometric proofs prove if certain shapes are congruent, whether they are not. They can also prove if sides are equal when values are not given, if a certain shape fits certain criteria, and can prove the length of certain lines when the values are not given.

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Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc
aivan3 [116]

1) 4.55

2) Short hit

Step-by-step explanation:

1)

The table containing the score and the relative probability of each score is:

Score 3 4 5 6 7

Probability 0.15 0.40 0.25 0.15 0.05

Here we call

X = Miguel's score on the Water Hole

The expected value of a certain variable X is given by:

E(X)=\sum x_i p_i

where

x_i are all the possible values that the variable X can take

p_i is the probability that X=x_i

Therefore in this problem, the expected value of MIguel's score is given by:

E(X)=3\cdot 0.15 + 4\cdot 0.40 + 5\cdot 0.25 + 6\cdot 0.15 + 7\cdot 0.05=4.55

2)

In this problem, we call:

X = Miguel's score on the Water Hole

Here we have that:

- If the long hit is successfull, the expected value of X is

E(X)=4.2

- Instead, if the long hit fails, the expected value of X is

E(X)=5.4

Here we also know that the probability of a successfull long hit is

p(L)=0.4

Which means that the probabilty of an unsuccessfull long hit is

p(L^c)=1-p(L)=1-0.4=0.6

Therefore, the expected value of X if Miguel chooses the long hit approach is:

E(X)=p(L)\cdot 4.2 + p(L^C)\cdot 5.4 = 0.4\cdot 4.2 + 0.6\cdot 5.4 =4.92

In part 1) of the problem, we saw that the expected value for the short hit was instead

E(X)=4.55

Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.

8 0
3 years ago
Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares
Alla [95]
Let the measure of side AB be x, then, the measue of side AE is given by

AE=\sqrt{9^2-x^2}.

Now, ABCD is a square of size x, thus the area of square ABCD is given by

Area=x^2

Also, AEFG is a square of size \sqrt{9^2-x^2}, thus, the area of square AEFG is given by

Area=\left(\sqrt{9^2-x^2}\right)^2=9^2-x^2=81-x^2

<span>The sum of the areas of the two squares ABCD and AEFG is given by

x^2+81-x^2=81

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>
8 0
3 years ago
What is the value of 2 b + 24 equals 30​
madam [21]
The answer is b = 3. you subtract 24 from bothe sides and then divide by 2.
5 0
3 years ago
Read 2 more answers
How to write 25 percent of N
Eva8 [605]
25÷100=0.25 0.25×n=the percentage Or 0.25n Or 0.25•n
8 0
3 years ago
Read 2 more answers
Does anyone know the answer for the question below.
8090 [49]

Answer: option C

Step-by-step explanation:

The diagram of the triangle is shown in the attached photo. The triangle is a right angle triangle ABC

Assuming the given angle is #,

Recalling the trigonometric ratio,

tan # = opposite / adjacent

If tan # = 4, it means

opposite / adjacent = 4/1

Therefore, opposite = 4 and adjacent = 1

Applying Pythagoras theorem,

Hypotenuse^2 = opposite ^2 + adjacent ^2

Hypotenuse = AC

Opposite = 4

Adjacent = 1

AC^2 = 4^2 + 1^2 = 17

AC = ± √17

To determine cos #, we would apply another trigonometric ratio,

Cos# = adjacent /hypotenuse

Cos# = 1/±√17

Cos # =-1 /√17 or 1/√17

8 0
3 years ago
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