The fractions which cannbe formed are: 2/3, 3/2, 2/5, 5/2, 3/5 and 5/3.
Now, we find the products with the third number:
2/3*5= 10/3 = 3.33 > 2
3/2*5 = 15 >2= 7.5 > 2
2/5*3= 6/5 (rejected)
5/2*3 = 15/2 > 2
3/5*2= 6/5 (rejected)
5/3*2 = 15/2 = 7.5> 2
9514 1404 393
Answer:
the origin
Step-by-step explanation:
Both terms are of odd degree, so the function is an odd function. It is symmetrical with respect to the origin.
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If you recast this as y = f(x), then ...
f(x) = x^(3/5)
When we look at f(-x), we find ...
f(-x) = ((-x)^3)^(1/5) = -(x^3)^(1/5) = -(x^(3/5)) = -f(x)
An odd root of a number has the same sign as the number.
When f(-x) = -f(x), the function is odd and symmetrical about the origin.
28 .to explain they want to know the missing side and the triangles are equal to each-other just one is projected smaller than the other . So the one with 16 16 and 24 is the smaller one . The difference between 24-16 is 8 . And In the bigger one the sides 20 and 20 where given so since the smaller one is equal to the bigger one you just do 20+8=28
13,207,982,634 x⁵y⁶
Step-by-step explanation:
We understand that in Binomial Theorem, expounding of polynomial functions, we have a rule that also involves the use of Pascal's Triangle to find the Coefficients that will be used to multiply each variable as the polynomial function is multiplied by itself several times;
(3x + 7y)^11 = ₁₁C₀ (3x)¹¹(7y)⁰ + ₁₁C₁ (3x)¹⁰(7y)¹ + ₁₁C₂ (3x)⁹(7y)² + ₁₁C₃ (3x)⁸(7y)³ + ₁₁C₄ (3x)⁷(7y)⁴ + ₁₁C₅ (3x)⁶(7y)⁵ + ₁₁C₆ (3x)⁵(7y)⁶....
The 7th term in our case is;
₁₁C₆ (3x)⁵(7y)⁶
According to the attached Pascals Triangle, the coefficient for our term should be 462, so;
462 (3x)⁵(7y)⁶
= 462 (243x⁵) (117,649y⁶)
= 13,207,982,634 x⁵y⁶
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Answer:
the answer is D according to my scorrs