Question

What did I do wrong?!

Answer 1

(3n-2) x (4n+1) =0

All you need to do is to find what value of n makes each factor equal 0.

First Term:
3n-2 = 0
3n = 2
n = 2/3

Second Term:

4n+1 = 0
4n = -1
n = -1/4

n ={2/3, -1/4}