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fomenos
3 years ago
11

A gym coach needs to buy badminton supplies. Rackets cost $10 each, and a pack of birdies costs $4. The coach has a budget of $1

00 and needs at least as many packs of birdies as rackets. Which graph shows the possible number of rackets and packs of birdies that the coach can buy?

Mathematics
2 answers:
Rasek [7]3 years ago
8 0
I think that the 2 or 4 one are right. This one is hard for me too but just hope that you get right and hope that it is right.
erastovalidia [21]3 years ago
4 0
Graph #4. Shaded portions of the graph represent the possible solutions. The maximum amount of birdies the coach can buy is 25 (4x25=100), which is why the red does not go further than 25. The maximum amount of rackets the coach can buy is 10 (10x10=100). The purple area represents numbers of BOTH rackets and birdies the coach can buy.
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How do you Solve d+7/−3=4?
vova2212 [387]

Answer:

One solution was found :

                  d = 19/3 = 6.333

Step-by-step explanation:

Step by step solution :

Step  1  :

            7

Simplify   ——

           -3

Equation at the end of step  1  :

        7    

 (d +  ——) -  4  = 0

       -3    

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  -3  as the denominator :

         d     d • -3

    d =  —  =  ——————

         1       -3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

d • 3 + 7 • -1     3d - 7

——————————————  =  ——————

      3              3  

Equation at the end of step  2  :

 (3d - 7)    

 ———————— -  4  = 0

    3        

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

        4     4 • 3

   4 =  —  =  —————

        1       3  

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

(3d-7) - (4 • 3)     3d - 19

————————————————  =  ———————

       3                3  

Equation at the end of step  3  :

 3d - 19

 ———————  = 0

    3  

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 3d-19

 ————— • 3 = 0 • 3

   3  

Now, on the left hand side, the  3  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  3d-19  = 0

Solving a Single Variable Equation :

4.2      Solve  :    3d-19 = 0

Add  19  to both sides of the equation :

                     3d = 19

Divide both sides of the equation by 3:

                    d = 19/3 = 6.333

One solution was found :

                  d = 19/3 = 6.333

6 0
3 years ago
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kumpel [21]

Answer:

Step-by-step explanation:

The answer is 10.0

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