When y=2 and y=5
1. 2y-1 and (3y-5+y or 4y-5)
when y=2 ; 2(2)-1 = 3 and 4(2)-5=3
when y=5 ; 2(5)-1 = 9 and 4(5)-5=15
----nonequivalent-----
2.5y+4 and (7y+4-2y or 5y+4)
so you don't have to place any value in because 5y+4 and 7y+4-2y are equal,
whatever you place any value in, it will be all the same then
-----equivalent------
and no need to find more
1, it is shifted 4 units up
Answer:
x = 13 smaller integer
x + 2 = 15 the other integer
Step-by-step explanation:
x = the smaller integer
x + 2 = the next integer
7(x) = 61 + 2(x + 2)
7x = 61 + 2x +4
5x = 61 + 4
5x = 65
x = 13 smaller integer
x + 2 = 15 the other integer
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