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Fudgin [204]
3 years ago
8

Each square and figure DNE has a side length of one unit compare the area of the two figures which figure has more area how much

more explain or show your reasoning

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

✅Figure E has more area

✅Figure E has 5.14 units² much more than Figure D.

Step-by-step explanation:

The logic to solving this kind of problem is to decompose and each of the figure to find out how many squares and circles are there in each figure, them calculate the area of each figure using the formula for area of square and area of a circle.

✍️Figure D:

Figure D is composed of 2 squares and 4 semicircles (2 full circles).

Since side length of 1 square = 1 unit, therefore, radius of the semi-circle/circle = 1 unit.

Area of the 2 squares = 2(s²) = 2(1²) = 2 unit²

Area of the 2 full circles = 2(πr²) = 2(3.14*1²) = 6.28 unit²

Area of Figure D = 2 + 6.28 = 8.28 unit²

✍️Figure E:

Figure E is composed of 4 squares and 6 quarter circles (3 full circles).

Area of the 4 squares = 4(s²) = 4(1²) = 4 unit²

Area of the 3 full circles = 3(πr²) = 3(3.14*1²) = 9.42 units²

Area of figure E = 4 + 9.42 = 13.42 unit²

✅Therefore, we can conclude that Figure E has more area.

✅Figure E has 5.14 unit² more area than Figure D (13.42 - 8.28 = 5.14).

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Answer:

v = 25

Step-by-step explanation:

The crucial information you need to know to solve this is to realize that HI and GH are the same length. However, why they are equal is not immediately obvious.

Both sides of the middle line (HF) are symmetrical, since G and I are the same distance away from the line, and they both lie on a line perpendicular to the middle line.

Note: we know they're the same distance away due to the small red marks in the lines, indicating that they're the same length.

The angles at G and I in the triangles are also the same, as the lines from G and I both meet at H. If they were different angles, they would each hit a different point on the middle line.

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Answer: v = 25

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