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Fudgin [204]
3 years ago
8

Each square and figure DNE has a side length of one unit compare the area of the two figures which figure has more area how much

more explain or show your reasoning

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

✅Figure E has more area

✅Figure E has 5.14 units² much more than Figure D.

Step-by-step explanation:

The logic to solving this kind of problem is to decompose and each of the figure to find out how many squares and circles are there in each figure, them calculate the area of each figure using the formula for area of square and area of a circle.

✍️Figure D:

Figure D is composed of 2 squares and 4 semicircles (2 full circles).

Since side length of 1 square = 1 unit, therefore, radius of the semi-circle/circle = 1 unit.

Area of the 2 squares = 2(s²) = 2(1²) = 2 unit²

Area of the 2 full circles = 2(πr²) = 2(3.14*1²) = 6.28 unit²

Area of Figure D = 2 + 6.28 = 8.28 unit²

✍️Figure E:

Figure E is composed of 4 squares and 6 quarter circles (3 full circles).

Area of the 4 squares = 4(s²) = 4(1²) = 4 unit²

Area of the 3 full circles = 3(πr²) = 3(3.14*1²) = 9.42 units²

Area of figure E = 4 + 9.42 = 13.42 unit²

✅Therefore, we can conclude that Figure E has more area.

✅Figure E has 5.14 unit² more area than Figure D (13.42 - 8.28 = 5.14).

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Answer:

C. N = 400 / 10

Step-by-step explanation:

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Total amount earned = Lawn-cutting Bank Account + Amount paid for gas

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= $400

Amount earned per every lawn he mowed = $10

How Many Lawns Did He mow?

Let N = number of lawns he mowed

N = Total amount earned / Amount earned per every lawn he mowed

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2 years ago
3) Caleb's cellphone says that it is 20% charged. He has 45
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Step-by-step explanation:

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3 years ago
The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio
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Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

a)

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

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P-value = ~0

Since P-vale < 0.01 , we will reject null hypothesis.

The data suggest that true average stopping ditance exceeds the maximum.

b)

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mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

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z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

P-value = 0.0037 Answer

c)

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

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The probabilities obtained in part c are comparatively higher than that of part b.

d)

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

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3 years ago
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Ok. So… Let's see if I can solve this one.

So since they wanted 4.2% out of the 640,000 Abdull makes, we can move the decimal(4.2%) to the left twice. Which will get .042 . The afterword-that will allow us to multiply 640,000 dollar with .042 . Which mean Adbull has receive 26,880 cash that year.

Answer for “A” = 26,880

Ok so his annual salary plus his commission. That means his 400 dollar (per month) plus the amount on the sales commission. Which mean… 400 dollar(Monthly) plus 26,880 dollars. Which will get us 27,280

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B = 27,280

(Im not sure about answer B because Im not sure if they are talking about yearly price for both or monthly payment for 400 dollar plus the monthly commission.) But overall, their,you have your answer.

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