What is 7.8 x 10^-3 in standard form

NEED ANSWER QUICK!!

dybincka [34]

Answer:

$192

Step-by-step explanation:

2400/48=50

50x3.84=192

3 0

2 years ago

I'm not sure how to start solving the problem (I'm not sure if I need to find circumference/perimeter bc it's asking how much pa

katrin [286]

The answer would be approximately 56.52 inches squared.

You are suppose to find the lateral surface area, since the label only go around the can, excluding the top and bottom.
To find the lateral surface area, you'd need to find the circumference of the circle, and then multiply that by the height.
Since C = πd, 3.14..*3 ≈ 9.42. And 9.42*6 = 56.52. Conclusively, the approximate amount of paper needed to make the can's label would be about 56.52 inches squared.

8 0

3 years ago

Prove that the value of expression 9^7+3^12 is divisible by 90.

snow_tiger [21]

9^7=4782969 and 3^12=531441 and when you add 4782969 and 531441 together you get 5314410. Then divide that number by 90 and get 59049

3 0

3 years ago

A baseball team won 40% of its first 30 games. The team then won 65% of its next 60 games. Approximately what percent of the gam

satela [25.4K]

the first team won 10%over of is game then the next team won5%over it team

6 0

3 years ago

Trials in an experiment with a polygraph include 98 results that include 24 cases of wrong results and 74 cases of correct resul

madreJ [45]

Answer:

$z=\frac{0.755 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-1.114$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of successes is not significantly less than 0.8 or 80%

Step-by-step explanation:

Data given and notation

n=98 represent the random sample taken

X=74 represent the number of cases correct

$\hat p=\frac{74}{98}=0.755$ estimated proportion of successes

$p_o=0.8$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of successes is less than 0.8.:

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.755 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-1.114$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of successes is not significantly less than 0.8 or 80%

5 0

2 years ago