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3 years ago

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At 8:00 am the smiths left a camp ground, driving at 48 mi/h. At 8:20 am the Garcia's left the same campground and followed the

same route, driving at 60 mi/h. At what time did they overtake the Smiths

1 answer:

Fantom [35]3 years ago

3 0

Answer:

9:40 am

Step-by-step explanation:

Let time taken from when Smith left compound to when Garcia overtakes Smith's car be represented by y

After y hours, Smith has covered 48*y=48y miles

Similarly, due to a difference of 20 minutes which is 20/60=1/3 hours, Garcia moves a distance of

60(y-1/3)

Equating both distances to be the same

60y-20=48y

12y=20

y=20/12=5/3 hours

Converted to minutes

5/3*60=100 minutes= 1 hr 40 mins

Therefore, adding 100 minutes to to starting time of Smith

8:00+1:40=9:40 am

The time that Garcia overtakes Smith is 9:40am

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