Answer:
C is correct
Step-by-step explanation:
Firstly, we have to solve for x in the solution set of the inequality
We have this as follows;
x + 2 ≥ 6
x ≥ 6-2
x ≥ 4
To graph this, we consider the middle sign which is greater than or equal to
So, the inequality sign has to face the right side
secondly, it has to be shaded on the point 4 due to the fact that it has the ‘equal to’ beneath the single inequality symbol
so, the correct answer here is option C
Answer:
974
Step-by-step explanation:
(91.01)*(10.7)
91.01*(10.7)
91.01*10.7
973.80700
974
Answer:
12/13
Step-by-step explanation:
We know that cosine is the adjacent side divided by the hypotenuse in a right triangle.
The adjacent side to angle C is BC
The hypotenuse is AC because it is opposite to the right angle
So...
cosine is (BC)/(AC)
36/39
12/13
Answer:
The value of k is -7
Step-by-step explanation:
We are given the graph of f(x) and g(x). If g(x)=f(x)+k
If we shift f(x) k unit vertical get g(x).
If k>0 then shift up
If k<0 then shift down.
f(x) and g(x) are both parabola curve.
First we find the vertex of f(x) and g(x)
Vertex of f(x) = (3,1)
Vertex of g(x) = (3,-6)
We can see change in y co-ordinate only.
f(x) shift 7 unit down to get g(x)
g(x)=f(x)-7
Therefore, The value of k is -7
Answer:
Mean and IQR
Step-by-step explanation:
The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.
For company A:
Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.
Hence, the mean will be the best measure of centre rather Than the median in this case.
For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.
