0.1 is 10 times as much as what ?

One angle of a right triangle measures 10°. What is the measure of the other acute angle?

Andrei [34K]

Answer:

80 degrees

Step-by-step explanation:

Do 90 plus 10.

The do 180 minus 100

because a triangle adds up to 180

5 0

3 years ago

Read 2 more answers

Find a number that is 5 times as much as 4 divided by 2

barxatty [35]

10....

4 x 5 ÷ 2 is 10

4 0

4 years ago

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PO What is the slope of a line that goes through the following 2 points? (-12,-5) (0, -8)

balandron [24]

Answer:

-1/4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-(-5))/(0-(-12))

m=(-8+5)/(0+12)

m=-3/12

simplify

m=-1/4

Please mark me as Brainliest if you're satisfied with the answer.

3 0

3 years ago

Please can anyone send a question in law of indices I really need it now

DaniilM [7]

Answer:

I think this is a pretty good question of law of indices

Step-by-step explanation:

Given that

$(9^p)(27^q)=3^n\\$

a) express n in terms of p and q ,

b) hence if p = 1 and q = 2 find the value of n

Solution to part a)

$(9^p)(27^q)=3^n\\\\$

Simplify the equation and how do we do that? As we can see that 9 can also be written as 3^2 and 27 can be written as 3^3 we can rewrite the following equation like this,

$(3^2)^p(3^3)^q=3^n\\$

now we multiply p with 2 and

multiply q with 3 respectively,

$(3^{2p})(3^{3q})=3^n\\$

now since the bases are same and are multiplying the exponents will add themselves like this, in this equation the number 3 is the base

$3^{2p+3q}=3^n\\$

now since the bases on the left hand side and on the right hand side are equal the exponents will also be equal so now,

$2p+3q=n\\$

hence n is expressed in terms of p and q

Solution to part b)

if p = 1 and q = 2 we plug in these values in the above equation we found for n

n = 2p + 3q

n = 2(1) + 3(2)

n = 2 + 6

n = 7

6 0

3 years ago

Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca

KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean breaking weight = 768.2 lb

s = sample standard deviation = 15.1 lb

n = sample of cables = 45

$\mu$ = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.02 < $t_4_4$ < 2.02) = 0.95 {As the critical value of t at 44 degree

of freedom are -2.02 & 2.02 with P = 2.5%}

P(-2.02 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.02) = 0.95

P( $-2.02 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }$ , $768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }$ ]

= [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0

3 years ago