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Genrish500 [490]
3 years ago
10

Sam is hired for a 20-day period. On days that he works, he earns $60. For each day that he does not work, $30 is subtracted fro

m his earnings. At the end of the 20-day period, he received $660. How many days did he not work?A) 2B) 4C) 6D) 3
Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0

Answer:

He did not work for 6 days

Step-by-step explanation:

Sam is hired for a 20-day period.

Let x be the no. of days he did not work

So, No. of days he worked = 20-x

he earns per working day = $60

So, he earns for (20-x) days = 60(20-x)

For each day that he does not work, $30 is subtracted from his earnings.

So, Amount deducted for x days = 30x

So, His earning for 20 days =60(20-x)-30x

We are given that At the end of the 20-day period, he received $660

So, 60(20-x)-30x=660

1200-60x-30x=660

1200-90x=660

1200-660=90x

540=90x

\frac{540}{90}=x

6=x

So, he did not work for 6 days

So, Option C is true

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Find the 76th term of the arithmetic sequences 16 14 12
grigory [225]

Answer:

a₇₆ = - 134

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 16 and d = a₂ - a₁ = 14 - 16 = - 2, then

a₇₆ = 16 + (75 × - 2) = 16 - 150 = - 134

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3 years ago
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4 0
2 years ago
Holly missed 8 of 185 school days this year. Approximately what percent of school days was Holly in attendance?
natulia [17]
8/185 = 4.3 % 
That is the number of days she missed so she was in attendance

100-4 = 96%
3 0
3 years ago
Read 2 more answers
Solve the inequality -6c&lt; -12
sweet [91]

Answer: c<2

Step-by-step explanation:

-6c<-12

c<-12/-6

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7 0
3 years ago
In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes
ale4655 [162]

Answer:

The sample mean is \bar{x}=14.371 min.

The sample standard deviation is \sigma = 18.889 min.

Step-by-step explanation:

We have the following data set:

\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

\bar{x} = \frac{{\sum}x}{n}

where, n is the number of values in the data set.

\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }

The mean of a sample is  \bar{x}=14.371.

Create the below table.

Find the sum of numbers in the last column to get.

\sum{\left(x_i - \overline{X}\right)^2} = 6422.0982

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 6422.0982 }{ 19 - 1} } \approx 18.889

7 0
3 years ago
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