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9966 [12]
3 years ago
7

Help me solve C=AB+D for B.​

Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0
C=AB+D
C-D=AB
C/A-D/A=B
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From the sum of 2 and -11, subtract the sum of 2 and -6<br>​
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3 years ago
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A number cube has faces numbered 1 through 6, and a coin has two sides, "heads" and "tails". The
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Answer:

The <em>required probability</em> is \dfrac{1}{12}.

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Let <em>A </em>be the event of rolling the number cube.

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Total number of possibilities of rolling the number cube and tossing the coin are <em>12 </em>here.

\{(1,H),(2,H),(3,H),(4,H),(5,H),(6,H),(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)\}

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P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

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Number of favorable cases are <em>1 </em>and total cases are <em>12</em>.

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2 years ago
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IT WOULD BE "D" I BELIEVE

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Angles 6 and 7, because they are alternate along the transversal.

Also angles 1 and 4.
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