He paid him : 24t + 15
for 3 hrs...
24(3) + 15 = 72 + 15 = $ 87
Given:
<span>11 11.5 10.5 17 14.5 14.5 18 17 19
Arrange in chronological order from least to greatest.
10.5 ; 11 ; 11.5 ; 14.5 ; 14.5 ; 17 ; 17 ; 18 ; 19
</span><span>I used an online lower and upper fence calculator to get the necessary data.
Minimum: 10.5
Maximum: 19
Q1: 11.25
Q2 or median: 14.5
Q3: 17.5
Interquartile range can be solved by subtracting the value of Q1 from the value of Q3
IQR = Q3 - Q1
IQR = 17.5 - 11.25
IQR = 6.25 CHOICE A. </span>
The length of the rug would be 18m
LxW=A
14x18=252
4500 meters. You find this by adding 1/3 and 2/5 which equals 11/15. This means that the remaining 4/15 is 1200 meters long. Divide 1200 by 4 in order to find the distance per 1/15 and you get 300. Multiply 300 with 15 to get the total distance of the race.
You cannot add row 2 to column 3 because they have different dimensions. You can do any of the other operations, but the only one that makes any sort of sense is ...
Multiply row 2 by -1 and add it to row 3
_____
It makes no sense to multiply a row by zero. That makes the entire row zero and makes the matrix useless for finding any sort of solution.
You can switch columns, but that doesn't get you any closer to a solution here.
If I were trying to find a solution, I might
switch rows 1 and 2
multiply the new row 1 by -3 and add it to the new row 2
multiply the new row 1 by 2 and add it to row 3
This sequence of operations will make the first column [1 0 0], reducing the problem to 2×2 from 3×3.
