It would go in quarderent 4
The question states that both parts of Noshi's desk were shaped like trapezoids and both had a height of 3.
We know that the formula for area of a trapezoid is (a+b)/2 * h, where a and b are bases of the trapezoid and h is the height. Note: This is like any other form of trying to find the area, because we are doing base times height, however, we need to divide the sum of the bases by 2 to find the average base length.
Let's call the first trapezoid on the left Trapezoid A and the second slanted trapezoid Trapezoid B.
Area of Trapezoid A = (a+b)/2 * h = (5+8)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
Area of Trapezoid B = (a+b)/2 * h = (4+9)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
To find the area of Noshi's total desk, we simply need to add the areas of Trapezoid A and Trapezoid B together.
19.5 feet + 19.5 feet = 39 feet
Therefore, the area of Noshi's desk is 39 feet.
Hope this helps! :)
Answer:
(2,4)
Step-by-step explanation:
the point where the lines intercept is the solution, so it is (2,4)
Step-by-step explanation:
sol;
x+1=y...(1)
3y-7=2x....(2)
or, 3(x+1)-72x [from (1)]
or, 3x+3-7=2x
or, 3x-2x=7-3
x=4
now,
putting the value of x in (1)
y=x+1
=4+1
=5
PR and SQ are the diagonal of PQRS.
