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AleksandrR [38]
3 years ago
11

Help with 5,6,8 please

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0
5. B, The answer is the only one that is false
6. G, Only reasonable answer
7. D, 3/5 is equivelant to 180/300

Hope this helps :D
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Is 11 rational or irrational
PolarNik [594]
11 is irrational cause it is on the number line
most numbers in the number line are irrational numbers
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3 years ago
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Whats 0 divide 0 i really want to know
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Answer

N/A

Step-by-step explanation:

lets take a step into our imaginations, ok?

So when you divide, you're basically splitting the numerator into as many parts as the denominator.

imagine you have a chocolate bar, and it has 6 pieces and you want to split it evenly between your 3 friends.

you split it into three equal parts to get 2 pieces per person.

When you divide 0 by 0, your splitting 0 chocolate bars into 0 equal portions, which is why this problem isn't solvable.

4 0
3 years ago
Given the relation y = -4x2 -8 if the input is 2 what is the output 8 -8 -16 -24
lara31 [8.8K]
-4x^2 - 8......input (x) = 2

-4(2^2) - 8 =
-4(4) - 8 =
-16 - 8 =
- 24 <==
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3 years ago
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Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
3 years ago
Which fraction is equivalent to 56%?
HACTEHA [7]
14 / 45

56 / 100 reduces to 14 / 45
5 0
3 years ago
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