Write an equation in slope intercept form, passes through (-1,-10), parallel to y=7

1 answer:

3 0

The line y=7 is a horizontal line with a slope of 0.
Slope intercept form of
y=mx+b

would be
y-y1=m(x-x1)
m=0 and point of (-1,-10)
y-(-10)=0

y=-10

You might be interested in

How do you solve this?

N76 [4]

Answer:

C. $y - 8 = -0.2 (x+10)$

Step-by-step explanation:

Slope

So first we need to find the slope in order to answer the question. To find the slope, we need to choose any two points from the table.

The slope equation is $m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ .

Let's use point (10,4) and point (15,3).

Now let's substitute those values into the slope equation. That gets to $m = \frac{3-4}{15-10}$ .

Now let's simplify that to $m = \frac{-1}{5} = -\frac{1}{5}$ . Therefore, the slope is $-\frac{1}{5}$ . In other words, it is also $-0.2$ .

Point-Slope Form

Now we need to plug in the numbers into the point slope form.

The point-slope form is $y - y_{1} = m(x-x_{1})$ .

Let's plug in the slope (m) into the equation. That gets to $y - y_{1} = -0.2 (x-x_{1})$ .

Now let's use (-10,8) in the equation since that's what it states in the problem. Doing that would lead to $y - 8 = -0.2 (x--10)$ . In other words, that is $y - 8 = -0.2 (x+10)$ .