What are the 5 pieces of data needed to make a box plot?

ROOTS AND CUBES Can someone please help me answer all 4 following?

Alex Ar [27]

NOTES:

squared (²) means multiply that number by itself 2 times
cubed (³) means multiply that number by itself 3 times
square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

Step-by-step explanation:

$\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41$

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Answer: (C) 10

Step-by-step explanation:

$\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}$

$=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}$

$=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9$

$=(7 - 2)\times \dfrac{1}{5}+9$

$=5 \times \dfrac{1}{5}+ 9$

$= 1 + 9$

$= 10$

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8² = 8 · 8 = 64 11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125 3³ = 3 · 3 · 3 = 27

$\sqrt{1600}=\sqrt{40\cdot 40}=40$ $\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4$

$\sqrt{144}=\sqrt{12\cdot 12}=12$ $\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20$

3 0

3 years ago

The measure of the supplement angle is fourteen times greater than its supplement

disa [49]

Let's assume you have supplement angle
$x$
Now when you talk about multiplication you can simply say...
$14x = y$
And that will give you the answer.

6 0

3 years ago

Please can someone answer this.

ivanzaharov [21]

Answer:

• x = -4, x = 0, x = 1

Step-by-step explanation:

x is a factor of all terms, so x=0 is a zero. (Eliminates choices 1 and 5.)

The sum of coefficients is 0, so x=1 is a zero. (Eliminates choices 3 and 4.)

Reversing the sign of the odd-degree terms gives signs of -++, so there is one sign change, hence one negative real root (by Descartes' rule of signs). This confirms choice 2 as the answer.

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Of course, your graphing calculator can answer this almost as quickly.

7 0

3 years ago

How many odd numbers with 4 different digits, can be formed using the digits 1, 2, 3, 4, 5, 6, 7, 8? (No repetition is allowed)

olga55 [171]

Answer:

840 ( D )

Step-by-step explanation:

GIVEN DIGITS : 1,2,3,4,5,6,7,8

Number of odd numbers = 4

Number of even numbers = 4

therefore the number of odd numbers with 4 different digits can be formed by the same way the number of even numbers ( without repetition )

Hence the number of ways odd numbers with 4 different digits = Total number of ways of forming 4 digit numbers / 2

8*7*6*5 = 1680 / 2 = 840 ways

6 0

3 years ago

Line L1 is horizontal and passes through (1,1). Line L2 is vertical and passes through (2,2). Find the point of intersection of

Sedaia [141]

(2,1)
that's going to be your answer.

4 0

3 years ago