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3 years ago

How to convert 11 to base 10

1 answer:

3 0

The given number which is 2A193A411 is written in Base 11. Base 11 number is also called undecimal system. The digits of Base 11 number are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. Since 10 is not accepted as a digit, then we have to substitute a variable which is A = 10. Hence, the digits of a Base 11 number are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, and A.

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SOMEONE PLEASE HELP EVEN IF ITS JUST WHAT YOU THINK PLEAE

Jet001 [13]

Dang it looks confusing
Is that Geometry

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3 years ago

Henry spent 1 hour 30 minutes less than Joey reading last week. Joey spent 50 minutes less than Pete. Pete spent 3 hours reading

Nookie1986 [14]

Answer: Henry read for a total of 40 minutes

Step-by-step explanation: 3:00 - 0:50 is 2:10 then 2:10 - 1:30= 40 minutes

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3 years ago

Read 2 more answers

Box and whisker plots please help!

kotykmax [81]

The correct answer is D. 100%
Each tick counts as 8 so the beginning of the plot would be at 28 which is only 2 from 30 and everything else is on the plot is greater than 30 so the answer would have to be D since 75% would be too little coverage of the plot

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2 years ago

What is the value of the x variable in the solution to the following system of equations? 4x − 3y = 3 5x − 4y = 3

andrew-mc [135]

Solve 4x − 3y = 3 and 5x − 4y = 3

Step 1: Solve for x in 4x-3y=3:
4x-3y=3
4x-3y+3y=3+3y [Add 3y to both sides]
4x=3y+3
 $\frac{4x}{4} = \frac{3x+3}{4}$ [Divide both sides by 4]
x= $\frac{3}{4}y+ \frac{3}{4}$

Step 2: Substitute $\frac{3}{4}y+ \frac{3}{4}$ for x in 5x-4y=3
5x-4y=3
5( $\frac{3}{4}y+ \frac{3}{4}$ )-4y=3
 $\frac{-1}{4}y+ \frac{15}{4} =3$
$\frac{-1}{4}y+ \frac{15}{4} - \frac{15}{4} =3- \frac{15}{4}$ [Subtract $\frac{15}{4}$ to both sides]
$\frac{-1}{4}y= \frac{-3}{4}$
$\frac{ \frac{-1}{4}y}{ \frac{-1}{4} }= \frac{\frac{-3}{4} }{ \frac{-1}{4}}$ [Divide both sides by $\frac{-1}{4}$ ]
y = 3

Step 3: Substitute 3 for y in x = $\frac{3}{4}y+ \frac{3}{4}$
$\frac{3}{4}y+ \frac{3}{4}$
$\frac{3}{4}(3)+ \frac{3}{4}$
x = 3

5 0

3 years ago

Find the cost of leveling a badminton court 132m long and 58 m broad at the rate of Rs. 80 per sq. m.

serg [7]

Answer:

Rs. 612,480

Step-by-step explanation:

Hi there,

Here the question asks us to find the cost of leveling a badminton court at the rate of Rs.80 per sq..

So by the word leveling we know that we have to find the area of the court in order to proceed further.

(I am assuming the court to be rectangular in shape).

Area of a rectangle = Length * Breadth

*Length = 132 meters

*Breadth = 58 meters

==> 132*58= 7656 m^2

So now that we got the area of the badminton court lets find the cost of leveling it ==>

Cost of leveling per meter^2 = Rs. 80

Area = 7656 m^2

==> 7656 * 80 = 612,480

So the cost would be Rs. 612,480

If you found this answer helpful please mark me as brainliest.

8 0

2 years ago

How to convert 11 to base 10​

How to convert 11 to base 10