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3 years ago

Make p the subject q - 2p = p + 4

Mathematics

1 answer:

solniwko [45]3 years ago

8 0

Q - 2p = p + 4
q - 4 = p + 2p
q - 4 = 3p
(q - 4) / 3 = p or q/3 - 4/3 = p

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Fifteen out of 60 participants scored between 17 and 21 on a test. what is the relative frequency of the class interval 17-21?

musickatia [10]

The frequency is how often something occurs. Here 15. It occurred 15 times that the participants scored in the interval given.

The relative frequency (expressed as a percent) looks at how often something occurred relative to the overall occurrences. Here 15/60 = 1/4 = 25%

The relative frequency is 25%

4 0

3 years ago

Read 2 more answers

Consider the following hypothesis test: H 0: 20 H a: < 20 A sample of 50 provided a sample mean of 19.4. The population stand

goblinko [34]

Answer: p-value is 0.016.

Step-by-step explanation:

Since we have given that

$H_0:\mu=20\\\\H_a:\mu$

Sample mean = 19.4

Sample size n = 50

Standard deviation = 2

We need to find the test statistic value which is given by

$z=\dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\\\z=\dfrac{19.4-20}{\dfrac{2}{\sqrt{50}}}\\\\\\z=\dfrac{-0.6}{0.28}\\\\z=-2.14$

p-value is given by

$P(Z>Z_{critical})\\\\=P(Z>-2.14)\\\\=0.016$

Hence, p-value is 0.016.

8 0

3 years ago

Convert into slope intercept form?

Alexeev081 [22]

<h3>Answer:</h3>

y = 2x + 5

<h3>Step-by-step explanation:</h3>

<u>Definitions</u>:

Slope Intercept form; y = mx + b

m = slope

b = y intercept

Step 1: Since the slope is given plug it into y = mx

y = 2x + b

Step 2: Plug a points' x and y into their corresponding spots to solve for b

(33) = 2(14) + b

Simplify and solve

33 = 28 + b

-28 -28

5 = b

Plug both your slope in and your y intercept into y = mx + b

y = 2x + 5

6 0

3 years ago

hello!! i would appreciate anyone’s help for this question and make sure you’re taking good care of ur self

crimeas [40]

Answer:

Is this a joke or wat if it is why

7 0

3 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago