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makvit [3.9K]
3 years ago
8

7+(53-3^{4} )/\sort{16}

Mathematics
1 answer:
topjm [15]3 years ago
4 0

Answer: 7+(53-3^{4} )/sqrt{16} = 0


Solution:

7+(53-3^{4} )/sqrt{16} =

7+(53-3*3*3*3)/4 =

7+(53-81)/4 =

7+(-28)/4 =

7-7 =

0

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Hey there, 29levelupchaye2!

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Using the distributive property to find the product (y — 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y
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I got a =16.
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8. A music store sells used CDs for $9. They buy used CDs for $4. You have $50 to
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3 years ago
10x + 1 = 2(3× + 5) - 1
MArishka [77]

Answer:

x = 2

Step-by-step explanation:

10x + 1 = 2(3x + 5) - 1

  1. mutlipy the 2 to the 3x and the 5
  2. you should get 10x + 1 = 6x + 10 - 1
  3. now you have to add the combine terms
  4. so it will now be 10x + 1 = 6x + 9
  5. now you.have to get the x's on one side and the constants (numbers alone) on the other side
  6. so you can subtract the 6x on both sides
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What would be the sum of the lengths of the first and second diagonals rounded to the nearest whole number?
drek231 [11]

Answer:

16.17684994

Step-by-step explanation:

First diagonal

x^2 = a^2 + b^2

x^2 = 5^2 + 6^2

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Second diagonal

x^2 = a^2 + b^2

x^2 = 7.810249676^2 + 3^2

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Sum of both diagonals

8.366600265 + 7.810249676

= 16.17684994

6 0
3 years ago
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