In the diagram, mŁACA<br> MACD<br> A<br> E<br> OD

Numbers that equal to 39

Natali5045456 [20]

Answer:

1 , 3 , 13 , and 39

Step-by-step explanation:

1 x 39 =39

3 x 13 = 39

13 x 3 = 39

39 x 1 =39

5 0

2 years ago

Read 2 more answers

Using the simple random sample of weights of women from a data set, we obtain these sample statistics: nequals45 and x overbar

Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : $n=45$

$\overline{x}=148.79\text{ lb}$

$\sigma=31.37\text{ lb}$

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = $\mu=148.79\text{ lb}$

b) The confidence interval for the population mean is given by :-

$\mu\ \pm E$ , where E is the margin of error.

Formula for Margin of error :-

$z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Significance level : $\alpha=1-0.90=0.1$

Critical value : $z_{\alpha/2}=z_{0.05}=\pm1.645$

Margin of error : $E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69$

Now, the 90% confidence interval for the population mean will be :-

$148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)$

Hence, the 90% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0

3 years ago

According to the latest survey the mean world lifespan is 68.8 years the university of Oregon wants to see if the average life s

pishuonlain [190]

Answer:

Step-by-step explanation:

We would set up the hypothesis test.

For the null hypothesis,

µ = 68.8

For the alternative hypothesis,

µ ≠ 68.8

This is a two tailed test.

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 26,

Degrees of freedom, df = n - 1 = 26 - 1 = 25

t = (x - µ)/(s/√n)

Where

x = sample mean = 72.8

µ = population mean = 68.8

s = samples standard deviation = 2.5

t = (72.8 - 68.8)/(2.5/√26) = 8.16

We would determine the p value using the t test calculator. It becomes

p < 0.00001

Assuming a significance level of 0.05, then

Since alpha, 0.05 > than the p value, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the average life span of the residence of Oregon differs from the world average.

4 0

3 years ago

Question Help

drek231 [11]

He drove 140 miles you take 245 divide by 7 then times by 4

8 0

3 years ago

While waiting for a video game to download, you notice that 30% of 32,000 kilobytes have been downloaded so far.

madam [21]

30%=30/100=0.3

0.3(32,000)=

9600kb downloaded

32 Megabite game? That'll be done is seconds on most connections. (the slowest of connections ive seen are about 20 mb/s)

3 0

4 years ago

In the diagram, mŁACA MACD A E OD