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3 years ago

Can I get an assist...

Mathematics

2 answers:

DerKrebs [107]3 years ago

3 0

Answer:

4; y-5=2(x+3)

Step-by-step explanation:

Question 1: 8y-18=14

8y=32

y=4

Question 2: y-5=2(x-(-3)

y-5=2(x+3)

Helen [10]3 years ago

3 0

Answer:

Question 1: y=4

Step-by-step explanation:

Question 1:

So first you have to open the parenthesis.

2 times 4y - 2 times 9= 14.

2 times 4=8 and you add an y; 8y

9 times 2= 18

8y- 18= 14

8y= 14+18

8y=32

32/8=y

y= 4

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5x + 3y - 15 + x<br><br> PLS HELP ASAP FAST

yarga [219]

Answer:

6x+3y-15

Step-by-step explanation:

take the x's add them up. take the y put it after the answer of the x's then subtract the y. (im just waffling)

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2 years ago

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True or false a square has both the characteristics of a rectangle and a rhombus

Serga [27]

The answer is true hop that helped

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3 years ago

I reallyy need help on this!<br> Thank you in advance

sattari [20]

Answer:828.96m^2

Step-by-step explanation:

radius(r)=8m

L=25m

π=3.14

total surface area of cone(tsa)=πxr^2+πxrxL

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3 0

3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

What is the answer to this problem 1/2=q 2/3?

Angelina_Jolie [31]

3/2 = 2q
q = 3/2 ÷ 2
q = 3/2 × 1/2
q = 3/4

6 0

3 years ago